SSC Junior Engineer Electrical Online Exam 2018 CPWD/CWC/MES Electrical Engineering 22-01-2018 Morning2
11. Which one of the following statement is TRUE about the Kirchhoff's voltage law?
he algebraic sum of all the voltages around any closed path is zero.
12. Which
one of the following is the CORRECT statement for superposition theorem?
The overall current in any part of a linear circuit is equal to the algebraic sum of the currents produced by each source separately.
13. Which one of the expression satisfies the condition of maximum power transfer theorem?
maximum power transfer theorem.
14. Determine the
value of current (in A) that flows through a resistor of 9 ohms, when the potential difference
between the ends of the resistor is 36 V.
Resistance R = 9 ohm
voltage V = 36 V
SO current I = V/R = 36/9 = 4A
.
15. What will be
the value of load impedance (in ohms) for transmitting maximum power from the source to load
when the source impedance is 8 + j4 ohms?
source impedance = 8 + j4
load impedance =?
Condition for maximum power transfer..
Load impedance = (Source impedance)* = (8 + j4)* = 8 – j4
.
16. Determine the value of current (in A) drawn from the voltage source for the electrical circuit
given below.
I = V/ R eq.
17. Determine the load resistance (in ohms) for a circuit when the maximum power transferred from
source of 80 V to the load is 80 W ?
P = 80 W
V = 80 V
Formula for maximum power transfer to the load is P = Vth * Vth / 4 Rth
Rth = 80*80/4*80 = 20 ohm
.
18. Determine the
Norton's resistance (in ohms) between terminals A and B for the circuit given below?
Norton resistance and thevenin resistance are equal. For thevenin resistance calculation we know fist open the terminal which across Rth need to calculate than replace independent source to their internal resistance. .
19. Determining the Thevenin's equivalent resistance (in ohms)
across the terminal a and b for the electrical circuit given below?
R = 0.5.
20. Determine the value of current (in A)
through 30 ohms resistor of the circuit given below?
I = 2amp.
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